Joining Toptal Web Development Community
I am a Computer Engineer and have one year experience of developing application on different online platform like fiver and freelancer but i didn't earn as much as i wanted and getting a project from that is very tiresome work. Then One of my friend is asked me to join Toptal as they provide quality work and handsome amount. And i have read about Toptal from different blogs and website, while reading that i have come to know many things about Toptal which differentiate that other freelancing websites. I have figured it out following things from that which i prefer Toptal:
Great Blog Post:
Anyway, I’ve just began the interview process at TopTal.com, and I really like to get in and become one of the freelancers who work there. If you’re a software engineer looking for work, I recommend that you do the same.
- Work provided by Toptal is according to the abilities of developer
- No tension of bidding on every project
- Amount paid by the Toptal is well enough for developer
- Great platform for beginners to start their professional career
Great Blog Post:
Anyway, I’ve just began the interview process at TopTal.com, and I really like to get in and become one of the freelancers who work there. If you’re a software engineer looking for work, I recommend that you do the same.
Tag :
Blogger
Form Validation
JavaScript Homework
Add the JavaScript code needed to enable auto-complete on this form. Whenever the checkbox is checked, the code should automatically copy the values from Shipping Name and Shipping Zip into the Billing Name and Billing Zip. If the checkbox is unchecked, the Billing Name and Billing Zip should go blank.
Suduko in Java
It's my semester project to make a Suduko game in Java. I worked very hard for it and at last I completed it. And I am giving you a complete description of it, it's very helpful for you.
 |
| Suduko Main View |
- DESCRIPTION
- Making GUI Of Game
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.border.Border;
import javax.swing.border.EtchedBorder;
public class GridGuiOne
extends MouseAdapter implements KeyListener,ActionListener,FocusListener {
JButton b1,b2,b3;
int ce=3;
int gridsel=0;
JFrame frame = new JFrame("Suduko");
JPanel main=new JPanel(new BorderLayout()); // Main Panel
JPanel puzzle=new JPanel(new GridLayout(1,0)); // Holds Suduko Grid and Buttons
JPanel Options=new JPanel(new GridLayout(3,0)); // Panel For JBUttons
JPanel Timer=new JPanel(new FlowLayout());
final JTextField[][] subPanels = new JTextField[9][9]; // 2D Array Of JTextFields[][]
JPanel[][] grid=new JPanel[3][3]; // 2D Array of Grid to hold JButtons
JPanel panel1= new JPanel(new GridLayout(3,3));
GridGuiOne()
{
builtOption();
builtGrid();
main.setSize(400,400);
Timer.add(Options);
main.add(Timer,BorderLayout.EAST);
main.add(puzzle,BorderLayout.CENTER);
frame.add(main);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setSize(600,450); frame.setVisible(true);}
- (a). Creating Options Panel OF the Game
In options Panel
I add three buttons:
Ø GENERATE
Ø CHECK
Ø EXIT
GENERATE: New Game Generate for the User
CHECK: Either Number is entered at right position or not
EXIT: Want To Quit
public void builtOption()
{
Options.setBorder(BorderFactory.createTitledBorder(" Options "));
b1=new JButton("GENERATE");
b2=new JButton("CHECK");
b3=new JButton("EXIT");
b1.setPreferredSize(new Dimension(100, 50));
b2.setPreferredSize(new Dimension(100, 50));
b3.setPreferredSize(new Dimension(100, 50));
Options.add(b1);
Options.add(b2);
Options.add(b3);
Options.setSize(400,400);
} |
| Option Panel For Game |
public void builtGrid()
{
Font s = new Font("Cooper", Font.ITALIC, 19);
Border bod = BorderFactory.createEtchedBorder( EtchedBorder.LOWERED, null,Color.white);
JPanel gridmain=new JPanel(new GridLayout(3,3));
for(int i=0;i<3;i++)
for(int j=0;j<3;j++)
{
grid[i][j]=new JPanel(new GridLayout(3,3));
grid[i][j].setBorder( bod );
gridmain.add(grid[i][j]);
}
// Adding array of Jbuttons(9x9) into the panels of(3x3)
int a=0,b=0;
for(int i=0; i<3; i++)
for(int j=0; j<3; j++,b++)
{
for(int k=0;k<3;k++)
{
for(int l=0;l<3; l++,a++)
{
if(b==9 )
break;
else
{
subPanels[b][a]=new JTextField("");
subPanels[b][a].setHorizontalAlignment(JTextField.CENTER);
subPanels[b][a].setForeground(Color.black);
subPanels[b][a].setFont(s);
subPanels[b][a].setBorder(BorderFactory.createLineBorder(Color.BLACK,1));
subPanels[b][a].setText(null);
subPanels[b][a].addActionListener(this);
subPanels[b][a].addKeyListener(this);
subPanels[b][a].addMouseListener(this);
subPanels[b][a].addFocusListener(this);
subPanels[b][a].setFocusable(true);
grid[k][l].add(subPanels[b][a]);
if(a==0 || a==2 || a==4 || a==6 || a==8)
{
subPanels[b][a].setBackground(new Color(143,188,143));
}
else
{
subPanels[b][a].setBackground(new Color(255,231,186));
}
} }
}
a=0;
}
b1.addActionListener(this);
b2.addActionListener(this);
b3.addActionListener(this);
puzzle.add(gridmain);
frame.setVisible(true);
}
1 2. Main
Logic Of Board
I
made 2D array of J Text Fields[9][9], which is placed in 3x3 of J Panel Grid.
It means that in every grid there is 9 buttons, which is placed in Grid in such
a way as shown in fig.
According
to this table, every button have fixed position in grid. [cell][grid].
[0][0]
|
[1][0]
|
[2][0]
|
[0][1]
|
[1][1]
|
[2][1]
|
[0][2]
|
[1][2]
|
[2][2]
|
[3][0]
|
[4][0]
|
[5][0]
|
[3][1]
|
[4][1]
|
[5][1]
|
[3][2]
|
[4][2]
|
[5][2]
|
[6][0]
|
[7][0]
|
[8][0]
|
[6][1]
|
[7][1]
|
[8][1]
|
[6][2]
|
[7][2]
|
[8][2]
|
[0][3]
|
[1][3]
|
[2][3]
|
[0][4]
|
[1][4]
|
[2][4]
|
[0][5]
|
[1][5]
|
[2][5]
|
[3][3]
|
[4][3]
|
[5][3]
|
[3][4]
|
[4][4]
|
[5][4]
|
[3][5]
|
[4][5]
|
[5][5]
|
[6][3]
|
[7][3]
|
[8][3]
|
[6][4]
|
[7][4]
|
[8][4]
|
[6][5]
|
[7][5]
|
[8][5]
|
[0][6]
|
[1][6]
|
[2][6]
|
[0][7]
|
[1][7]
|
[2][7]
|
[0][8]
|
[1][8]
|
[2][8]
|
[3][6]
|
[4][6]
|
[5][6]
|
[3][7]
|
[4][7]
|
[5][7]
|
[3][8]
|
[4][8]
|
[5][8]
|
[6][6]
|
[7][6]
|
[8][6]
|
[6][7]
|
[7][7]
|
[8][7]
|
[6][8]
|
[7][8]
|
[8][8]
|
At that logic the J Text
Fields are inserted into the panels. In whole program these positions matters a
lot.
1 3. Keep
Tracking Of Key Listener and Mouse Listener In J Text Field
As there are
81 JTextfields , which placed in 2D array named “subPanels[][]” in code. When user
selects a specific JTextfield in game, then we have to keep record of
that, so I made this function which points to the specified position during
game play.
As there is a Listener in java, which is
called FocusListener, ithas two Function.
1. FocusGained(FocusEvent
ae)
2. FocusLost(FocusEvent
ae)
This listener interacts or gave signal when the required field is under
focus, the focusGained performed and when the focus is lost then
focusLost is performed.
Here is the
code:
public void focusLost(FocusEvent arg0) {
for(int i=0; i<=8; i++)
{
for(int j=0; j<=8;j++)
{
{
if(j==0 || j==2 || j==4 || j==6 || j==8)
{
subPanels[i][j].setBackground(new Color(143,188,143));
//
}
else
{
subPanels[i][j].setBackground(new Color(255, 231 ,186));
}
}}
}
public void focusGained(FocusEvent arg0) {
int flag=0,i,j = 0;
// Finding at whic point the cursor is.
for( i=0; i<=8; i++)
{
for(j=0; j<=8;j++)
{
if(arg0.getSource()==subPanels[i][j])
{
flag++;
break;
}}
if(flag==1)
break;
}
System.out.print("Cursor" + i + " " + j);
printEventInfo(arg0,null,null,i,j);
a b. printEventInfor(Key
Listener, Focus Listener , Mouse Listener, int a, int b)
I made this function to control the key
Listener, either cursor is in main grid or out of grid. It controls the
keylistener, either cursor is moving down or upward or left or right in
maingrid. It controls it.
private void printEventInfo(FocusEvent focus,MouseEvent mouseLocat,KeyEvent keyLocat,int a,int b) {
if (keyLocat==null)
{
ce=a;
gridsel=b;
}
else
try
{
if (keyLocat.getKeyCode()== KeyEvent.VK_DOWN)
{
if((ce>=6 && ce<=8) && gridsel>=6)
{
ce-=6;
gridsel-=6;
subPanels[ce][gridsel].requestFocus();
}
else if((ce>=6 && ce<=8))
{
ce-=6;
gridsel+=3;
subPanels[ce][gridsel].requestFocus();
}
else
{
ce+=3;
subPanels[ce][gridsel].requestFocus();
}
}
else
if (keyLocat.getKeyCode() == KeyEvent.VK_UP)
{
if((ce>=0 && ce<=2) && (gridsel==0 || gridsel==1 ||gridsel==2 ))
{
ce+=6;
gridsel+=6;
subPanels[ce][gridsel].requestFocus();
}
else if((ce>=0 && ce<=2) && (gridsel>=3 && gridsel<=8) )
{
ce+=6;
gridsel-=3;
subPanels[ce][gridsel].requestFocus();
}
else
{
ce-=3;
subPanels[ce][gridsel].requestFocus();
}
}
else if (keyLocat.getKeyCode() == KeyEvent.VK_LEFT)
{
{
if((ce==0 || ce==3 || ce==6) && (gridsel==0 || gridsel==3 ||gridsel==6 ))
{
ce+=2;
gridsel+=2;
subPanels[ce][gridsel].requestFocus();
}
else if((ce==0 || ce==3 || ce==6) )
{
ce+=2;
gridsel-=1;
subPanels[ce][gridsel].requestFocus();
}
else {
ce-=1;
subPanels[ce][gridsel].requestFocus();
}
}
}
else if (keyLocat.getKeyCode() == KeyEvent.VK_RIGHT)
{
{
if((ce==2 || ce==5 || ce==8) && (gridsel==2 || gridsel==5 ||gridsel==8 ))
{
ce-=2;
gridsel-=2;
subPanels[ce][gridsel].requestFocus();
}
else if((ce==2 || ce==5 || ce==8) )
{
ce-=2;
gridsel+=1;
subPanels[ce][gridsel].requestFocus();
}
else {
ce+=1;
subPanels[ce][gridsel].requestFocus();
}
}
}
}
catch (ArrayIndexOutOfBoundsException e)
{
JOptionPane.showMessageDialog(null, e.getMessage());
}
finally{
}
}
3. Game
Starting Number
There
are two conditions in the starting of the game.
a. Fixed Numbers at Fixed
Locations
In this Condition we know the starting position of
the fixed text fields. In this way we can make a different levels of the game.likewise. I t is applied if you know the whole game , then you just set the game according to your own will.
subPanels[2][0].setText("4");
subPanels[2][0].setEditable(false);
subPanels[2][8].setText("7");
subPanels[2][8].setEditable(false);
b. Random Numbers at Random Locations
In the start of the game a random number is
generated at the random location of Board. But these numbers are according to
the rules of the game. I made a function
“logicCheck(int number, int cell, int grid, int
convert)” to check the condition of the starting game.
void randomNumberGenerate()
{
try{
boolean possible=true;
int Min1=1;
int Min=0;
int Max=8;
int Max1=9;
int randomNum=0;
String n;
int randomcell=0;
int randomgrid=0;
randomNum=(Min1 + (int)(Math.random() * ((Max1 - Min1) + 1)));
n=Integer.toString(randomNum);
randomcell=(Min + (int)(Math.random() * ((Max - Min) + 1)));
randomgrid=(Min + (int)(Math.random() * ((Max - Min) + 1)));
subPanels[randomcell][randomgrid].setText(n);
subPanels[randomcell][randomgrid].setEditable(false);
subPanels[randomcell][randomgrid].setForeground(Color.blue);
for(int i=0; i<10;i++)
for(int j=0; j<2; j++)
{
randomNum=(Min1 + (int)(Math.random() * ((Max1 - Min1) + 1)));
n=Integer.toString(randomNum);
randomcell=(Min + (int)(Math.random() * ((Max - Min) + 1)));
randomgrid=(Min + (int)(Math.random() * ((Max - Min) + 1)));
possible=logicCheck(randomNum,randomcell,randomgrid,1);
if(possible==true)
{
}
else
{
subPanels[randomcell][randomgrid].setText(n);
subPanels[randomcell][randomgrid].setEditable(false);
subPanels[randomcell][randomgrid].setForeground(Color.blue);
}
}
}
catch(ArrayIndexOutOfBoundsException ex){
System.out.print(ex.getMessage());
};}
4. Logic Check for The Game
I made a
function named, “logicCheck(int number,
int cell, int grid, int convert)” to check that either number which is
entered correctly in board or not.
That
function have a flexibility of controlling two logics. If the parameter convert
have value one then it controls the starting of game, it generates different
numbers. If the user press GENERATE button then it parameter convert is ON, and
the random numbers are generated at random position. And when the user press
check button it checks that at which position the numbers is entered wrongly.
When the number is entered at wrong position and user check it then that place
becomes Red. As shown in fig.
boolean logicCheck(int num, int row, int col,int convert)
{
String d = null;
int x=0;
int a=row;
int b=col;
boolean flag=true;
int moreCheck=0;
boolean random=false;
int counter1 = 0;
try
{
// Grid Checking
for(int i=0; i<9; i++)
{
if(((subPanels[i][col].getText().equals("")) || i==row ))
{
// i++;
}
else
{
d=subPanels[i][col].getText();
x=Integer.parseInt(d);
// System.out.print("Grid " + x + " ");
if(convert==0)
{
moreCheck=numberCheck(i,col,num,x);
if(moreCheck>0)
{
flag=true;
break;
}
else
flag=false;
}
else
random=randomLogic(num,x);
if(random==false)
{
counter1++;
}
}
// Row Checking
if(!flag || convert==1)
{
// System.out.print(" \n"+flag);
for(int c=0;c<3 ;c++,col++)
{
for(int j=0; j<3; j++)
{
if((row==2 || row==5 || row==8))
{
if((subPanels[row][col].getText().equals("")) || (row==a && col==b))
{
row-=2;
}
else
{
d=subPanels[row][col].getText();
x= Integer.parseInt(d);
// System.out.print("ROW " + x + " ");
if(convert==0)
{
moreCheck=numberCheck(row,col,num,x);
if(moreCheck>0)
{
flag=true;
break;
}
else
flag=false;
}
else
{
random=randomLogic(num,x);
if(random==false)
{
counter1++;
}
}
row-=2;
}
}
else
{
if((subPanels[row][col].getText().equals("")) || (row==a && col==b))
{
row++;
}
else
{
d=subPanels[row][col].getText();
x= Integer.parseInt(d);
if(convert==0)
{
moreCheck=numberCheck(row,col,num,x);
if(moreCheck>0)
{
flag=true;
break;
}
else
flag=false;
}
else
{
random=randomLogic(num,x);
if(random==false)
{
counter1++;
}
}
row++;
}
}
}
if(col==2 || col==5 || col==8)
col-=3;
}
}
//Coloumn Check
if(flag || convert==1)
{
for(int e=0;e<3 ;e++)
{
for(int j=0; j<3; j++)
{
if((row==6 || row==7 || row==8))
{
if((subPanels[row][col].getText().equals(""))||(row==a && col==b))
{
row-=6;
}
else
{
d=subPanels[row][col].getText();
x= Integer.parseInt(d);
if(convert==0)
numberCheck(row,col,num,x);
else
{
random=randomLogic(num,x);
if(random==false)
{
counter1++;
}
}
row-=6;
}
}
else
{
if((subPanels[row][col].getText().equals("")) || (row==a && col==b))
{
row+=3;
}
else
{
d=subPanels[row][col].getText();
x= Integer.parseInt(d);
if(convert==0)
numberCheck(row,col,num,x);
else
{
random=randomLogic(num,x);
if(random==false)
{
counter1++;
}
}
row+=3;
}
}
}
if(col==6 || col==7 || col==8)
col-=6;
else
col+=3;
}
}
}}
catch(NumberFormatException ex){};
if(counter1>0)
return random=true; // Number present already at any location
else
return random=false; // Number not present already
}
a a. Random
Generate Number Control
// Random Generate Number Control
boolean randomLogic(int num, int x) {
boolean flag=true;
if(num==x)
{
flag=false;
}
return flag;
}
b. Number Entered Checker
// Number Check
int numberCheck(int c, int d,int a, int b)
{
int check=0;
if(a==b)
{
subPanels[c][d].setBackground(Color.RED);
check++;
}
return check;
}
 |
| Required Field Is Empty
5.
Number Entered in Range
I also made a function which controls that either
number is entered in the range. The range is “1-9” , if anyone entered any thing except these, than the board is not
accepted it. It generates a pop up message
that Entered number correctly.
|
public void keyTyped(KeyEvent arg0) {
String num ;
int entrdNum;
// Checking Either Entered number is Valid
if (subPanels[ce][gridsel].getText().trim().length() != 0)
arg0.consume();
else
if ((arg0.getKeyChar() > '0' && arg0.getKeyChar() <= '9') || (arg0.getKeyChar() == KeyEvent.VK_BACK_SPACE)
|| (arg0.getKeyChar() == KeyEvent.VK_DELETE)) {
}
else
{
JOptionPane.showMessageDialog(null, "Enter Number 1-9");
arg0.consume();
}
// Get Entered number in Current Cell
if(arg0.getKeyChar()>=49 && arg0.getKeyChar()<=57)
{
num= KeyEvent.getKeyText(arg0.getKeyChar());
entrdNum=Integer.parseInt(num);
// System.out.print(entrdNum + " ");
}
}
 |
| Entered number is not in range
It detects that which button is pressed, and then work according
to that button.
|
public void actionPerformed(ActionEvent arg0)
{
String text=null;
int ef=0;
if(arg0.getSource()==b1)
{
for(int i=0; i<9;i++)
for(int j=0; j<9; j++)
{
subPanels[i][j].setText("");
subPanels[i][j].setEditable(true);
if(j==0 || j==2 || j==4 || j==6 || j==8)
{
subPanels[i][j].setBackground(new Color( 139, 71 ,93));
// subPanels[b][a].setBackground(Color.PINK);
}
else
{
subPanels[i][j].setBackground(Color.WHITE);
}
}
randomNumberGenerate();
}
else if(arg0.getSource()==b2)
{ // String text=null;
// int ef=0;
for(int i=0; i<9; i++)
{
for(int j=0; j<9; j++)
{
if(subPanels[j][i].getText().equals(""))
{
subPanels[j][i].setBackground(Color.RED);
}
else
{
text=subPanels[j][i].getText();
ef = Integer.parseInt(text);
System.out.print(ef);
logicCheck(ef,j,i,0);
}
}
}
}
else
{
JOptionPane.showMessageDialog(null,"Are You Sure, You Want To Exit");
frame.setVisible(false);
frame.dispose();
}
Thank's for reading this. If you have an any query contact me.
Here it is full cod. You can download it.
Here are some tutorial which are helpful for you.
1. Logical Suduko Solver In java
2. Backtracking to solve a sudoku puzzle
3. Suduko Solver
Code : https://www.dropbox.com/s/md4uds882lx77yq/Sudoko%20Code.txt
Full Description: https://www.dropbox.com/s/7fm03z20xo3xsaj/SUDUKO.docx
Tag :
Java
Desk hop -Simple and Secure Screen Sharing
- Can we access Other Computer ?
- Can we share our desktop with others ?
- Can we see others desktop ?
These are the question which every one thinks now a days.
And the response is "Yes", there is a software, with the help of, we can do all the things.
 |
| desk hop - Secure screen sharing |
Here is a link which'll give the answer of your all question. Download it from here.
Tag :
Softwares
How to delete row or column in Mat lab
Deletion Of Row In Mat lab
if there is a given a matrix e.g
A=[1 2 3; 4 5 6; 7 8 9; 10 11 12]
if we want to remove fourth row then there is a specific command in MAT LAB with the help of which we can eliminate a row as well column :
we normally represent a vector A(row,column)
A(1:3,1:3) //1:3 represents First three row and same 1:3 represent first three column
ans =
1 2 3
4 5 6
7 8 9
A(1:3,1:3) //1:3 represents First three row and same 1:3 represent first three column
ans =
1 2 3
4 5 6
7 8 9
Another Method
If you want to remove a specific row in any matrix then use this command
A(2,:)=[] // if you want to remove nth row then use this command A(n,:)
A =
1 2 3
7 8 9
10 11 12
A(2,:)=[] // if you want to remove nth row then use this command A(n,:)
A =
1 2 3
7 8 9
10 11 12
Deletion Of Column In Mat lab
A=[1 2 3; 4 5 6; 7 8 9; 10 11 12]
Same here if we want to remove a column then same we use a same method. E.g if we want to remove a third column from a matrix then we use a command
A(1:3, 1:2) // 1:3 represents one to third row and same 1:2 represent first two column
ans =
1 2
4 5
7 8
Another Method
If you want to remove a specific column in any matrix then use this command
A(,:2)=[] // if you want to remove nth row then use this command A(,:n)
A =
1 2 3
7 8 9
10 11 12
A(,:2)=[] // if you want to remove nth row then use this command A(,:n)
A =
1 2 3
7 8 9
10 11 12
Tag :
MAT LAB
Windows cannot be installed on this disk. The selected disk has an MBR partition table. On EFI systems, Windows can only installed on GPT disks
This is an error which i s occur when someone is installing a window on your PC. This is an hardware problem and can be solve. There's a lot methods to solve this. I mention here:
Method 1:
If your computer does not support UEFI, delete all the hard drives partitions and create a new partition (backup any data first):
1. Boot from the Windows DVD
2. Click Install Now
3. At the setup screen, click Custom (Advanced)
4. Click Drive Options
5. Select the partition(s) you want to format
6. Click Format - this will delete EVERYTHING on that partition
7. Create a new partition and select a partition to install Windows on.
8. Continue with install.
If the Windows install disk doesn’t work for the above you can do the following to reformat your drive:
1. Download and burn a Gparted ISO from here:
2. Boot from the Gparted disk.
3. Use Gparted to delete all partitions on the hard drive.
4. Under “Device” choose Create Partition Table to make a new partition table.
5. Create a NTFS partition (or you could wait and create a partition when installing Windows).
6. Then boot from the Windows install disk and install Windows.
Method 2:
If you install a window on your PC through USB, then first Check how to boot USB from Command Prompt.
When you boot from USB then there will be a problem in booting USB. This problem is commonly due to format of booting USB. If you boot USB in "Fat32" format then this problem is occured. Change the format to "NTFS" and then boot it. I hope that this will work on your PC.
Tag :
Issues
